C Programming

Practise Exercise 6

Compound Relationals and switch

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1. The statement that tests to see if sum is equal to 10 and total is less than 20, and if so, prints the text string "incorrect.", is

Statement 1

if( (sum = 10) && (total < 20) )
   printf("incorrect.");

Statement 2

if( (sum == 10) && (total < 20) )
   printf("incorrect.");

Statement 3

if( (sum == 10) || (total < 20) )
   printf("incorrect.");

2. if flag is 1 or letter is not an 'X', then assign the value 0 to exit_flag, else set exit_flag to 1.

Statement 1

if( (flag = 1) || (letter != 'X') )
   exit_flag = 0;
else
   exit_flag = 1;

Statement 2

if( (flag == 1) || (letter <> 'X') )
   exit_flag = 0;
else
   exit_flag = 1;

Statement 3

if( (flag == 1) || (letter != 'X') )
   exit_flag = 0;
else
   exit_flag = 1;

3. rewrite the following statements using a switch statement


		if( letter == 'X' )
			sum = 0;
		else if ( letter == 'Z' )
			valid_flag = 1;
		else if( letter == 'A' )
			sum = 1;
		else
			printf("Unknown letter -->%c\n", letter );

Statement 1

switch( letter ) {
   case 'X' : sum = 0; break;
   case 'Z' : valid_flag = 1; break;
   case 'A' : sum = 1; break;
   default  : printf( "Unknown letter -->%c\n", letter ); break;
}

Statement 2

switch( letter ) {
   case 'X' : sum = 0;
   case 'Z' : valid_flag = 1;
   case 'A' : sum = 1;
   default  : printf( "Unknown letter -->%c\n", letter );
}

Statement 3

switch( letter ) {
   case "X" : sum = 0; break;
   case "Z" : valid_flag = 1; break;
   case "A" : sum = 1; break;
   default  : printf( "Unknown letter -->%c\n", letter ); break;
}

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